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(R)=48000R-6R^2
We move all terms to the left:
(R)-(48000R-6R^2)=0
We get rid of parentheses
6R^2-48000R+R=0
We add all the numbers together, and all the variables
6R^2-47999R=0
a = 6; b = -47999; c = 0;
Δ = b2-4ac
Δ = -479992-4·6·0
Δ = 2303904001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2303904001}=47999$$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-47999)-47999}{2*6}=\frac{0}{12} =0 $$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-47999)+47999}{2*6}=\frac{95998}{12} =7999+5/6 $
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